ASP.NET实现微信抢红包代码实例

群里都在玩抢红包,抢了再发，发了再抢，简直是无聊，程序员感兴趣是的如何实现，这里简单说说实现思路，附上dome，代码有点low，好在是实现了，具体内容如下

正文

100块发30个红包

50块发13个红包

1块发10个红包

发红包需要满足以下几个条件

1.总金额不变2.每个红包都必须有钱3.尽量的均匀点,不然抢红包没什么意思了

实现思路1.首先要确定最小单位,这里是精确到分,我这里以int类型进行计算,得出的结果也全是int类型2.数据均匀,这里以1<n<(剩余金额/剩余红包数)*2,这里防止一个红包抢走大量的钱,这里需要写个递归,去检查数据值是否过大,50元发13个红包的第3图,就是因为没有检查数据,导致钱不平均,这个可以根据自己的玩法去设置.3.余数处理,当数据平均给20个红包,肯定跟总金额有所偏差,这时候我们就要多退少补,如果大于总金额,让红包金额多的去减少(总金额/总人数),如果还有剩余,就让第二多的去减少,直到补完这个空缺为止,反之亦然.4.打乱顺序,细心的园友可能发现,红包是有顺序规律的,我们必须简单的写个function去打乱它.　　

demo /// <summary> /// 抢红包 /// </summary> /// <param name="money"></param> /// <param name="num"></param> /// <returns></returns> public List<int> qhb(int money, int num) {int min = 1;int pjs = money / num;List<int> list = new List<int>();Random rnd = new Random();for (int i = 0; i < num; i++){int max = (money / (num - i)) * 2;int s = rnd.Next(min, max);s = checkmoney(s, min, max);list.Add(s);money -= s;}//前面数据都是合理的,结尾必须多退少补list = checklist(money, pjs, list);return list; }/// <summary> /// 余数处理 /// </summary> /// <param name="money"></param> /// <param name="list"></param> /// <returns></returns> public List<int> checklist(int money, int pjs, List<int> list) {if (money != 0){if (money > 0){List<int> list_order = maopao(list);//给最小if (money / pjs == 0){list_order[0] += money;}else{for (int i = 0; i < money / pjs + 1; i++){if (i == money / pjs){list_order[i] += (money - (money / pjs) * pjs);}else{list_order[i] += pjs;}}}return list_order;}else{List<int> list_order = maopao(list,"desc");//给最大if (money / pjs == 0){list_order[0] += money;}else{for (int i = 0; i < -(money / pjs) + 1; i++){if (i == -(money / pjs)){list_order[i] += (money - (money / pjs) * pjs);}else{list_order[i] -= pjs;}}}return list_order;}}return list; } /// <summary>/// 冒泡排序/// </summary>/// <param name="list"></param>/// <param name="order"></param>/// <returns></returns>public List<int> maopao(List<int> list,string order = "asc"){if (order != "asc"){for (int i = 0; i < list.Count; i++){for (int j = 0; j < list.Count - i - 1; j++){if (list[j + 1] > list[j]){int temp = list[j];list[j] = list[j + 1];list[j + 1] = temp;}}}}else{for (int i = 0; i < list.Count; i++){for (int j = 0; j < list.Count-i-1;j++){if (list[j+1] < list[j]){int temp = list[j];list[j] = list[j+1];list[j+1] = temp;}}}}return list; }/// <summary> /// 打乱顺序/// </summary>/// <param name="list"></param>/// <returns></returns> public List<int> suiji(List<int> list){Random rnd = new Random();for (int i = 0; i < list.Count; i++){int temp = list[i];int j = rnd.Next(0, list.Count-1);list[i] = list[j];list[j] = temp;}return list; }以上就是ASP.NET实现微信抢红包代码实例的详细内容，更多请关注小潘博客其它相关文章！