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MySQL5.7的JSON基本操作(代码示例)

时间:2020-09-22 05:20:07 作者:重庆seo小潘 来源:
本篇文章给大家带来的内容是关于MySQL5.7的JSON基本操作(代码示例),有一定的参考价值,有需要的朋友可以参考一下,希望对你有所帮助。 MySQL5.7的JSON基本操作 MySQL从5.7版本开始就支持JSON格式的数据,操作用起来挺方便的。 建表在新建表时字段类型可以

本篇文章给大家带来的内容是关于MySQL5.7的JSON基本操作(代码示例),有一定的参考价值,有需要的朋友可以参考一下,希望对你有所帮助。

MySQL5.7的JSON基本操作

MySQL从5.7版本开始就支持JSON格式的数据,操作用起来挺方便的。

建表在新建表时字段类型可以直接设置为json类型,比如我们创建一张表:mysql> CREATE TABLE `test_user`(`id` INT PRIMARY KEY AUTO_INCREMENT, `name` VARCHAR(50) NOT NULL, `info` JSON);json类型字段可以为NULL

插入数据:mysql> INSERT INTO test_user(`name`, `info`) VALUES('xiaoming','{"sex": 1, "age": 18, "nick_name": "小萌"}');json类型的字段必须时一个有效的json字符串

可以使用JSON_OBJECT()函数构造json对象:mysql> INSERT INTO test_user(`name`, `info`) VALUES('xiaohua', JSON_OBJECT("sex", 0, "age", 17));使用JSON_ARRAY()函数构造json数组:mysql> INSERT INTO test_user(`name`, `info`) VALUES('xiaozhang', JSON_OBJECT("sex", 1, "age", 19, "tag", JSON_ARRAY(3,5,90)));现在查看test_user表中的数据:mysql> select * from test_user; +----+-----------+--------------------------------------------+ | id | name| info|+----+-----------+--------------------------------------------+ |1 | xiaoming| {"age": 18, "sex": 1, "nick_name": "小萌"} | |2 | xiaohua| {"age": 17, "sex": 0}||3 | xiaozhang | {"age": 19, "sex": 1, "tag": [3, 5, 90]}| +----+-----------+--------------------------------------------+3 rows in set (0.04 sec)查询表达式: 对象为json列->'$.键', 数组为json列->'$.键[index]'mysql> select name, info->'$.nick_name', info->'$.sex', info->'$.tag[0]' from test_user; +-----------+---------------------+---------------+------------------+ | name| info->'$.nick_name' | info->'$.sex' | info->'$.tag[0]' | +-----------+---------------------+---------------+------------------+ | xiaoming| "小萌"| 1| NULL| | xiaohua| NULL| 0| NULL| | xiaozhang | NULL| 1| 3| +-----------+---------------------+---------------+------------------+ 3 rows in set (0.04 sec)等价于:对象为JSON_EXTRACT(json列 , '$.键'),数组为JSON_EXTRACT(json列 , '$.键[index]')mysql> select name, JSON_EXTRACT(info, '$.nick_name'), JSON_EXTRACT(info, '$.sex'), JSON_EXTRACT(info, '$.tag[0]')from test_user; +-----------+-----------------------------------+-----------------------------+--------------------------------+ | name| JSON_EXTRACT(info, '$.nick_name') | JSON_EXTRACT(info, '$.sex') | JSON_EXTRACT(info, '$.tag[0]') | +-----------+-----------------------------------+-----------------------------+--------------------------------+ | xiaoming| "小萌"| 1| NULL|| xiaohua| NULL| 0| NULL| | xiaozhang | NULL| 1| 3| +-----------+-----------------------------------+-----------------------------+--------------------------------+ 3 rows in set (0.04 sec)不过看到上面"小萌"是带双引号的,这不是我们想要的,可以用JSON_UNQUOTE函数将双引号去掉mysql> select name, JSON_UNQUOTE(info->'$.nick_name') from test_user where name='xiaoming'; +----------+-----------------------------------+ | name| JSON_UNQUOTE(info->'$.nick_name') | +----------+-----------------------------------+ | xiaoming | 小萌| +----------+-----------------------------------+ 1 row in set (0.05 sec)也可以直接使用操作符->>mysql> select name, info->>'$.nick_name' from test_user where name='xiaoming';+----------+----------------------+ | name| info->>'$.nick_name' | +----------+----------------------+ | xiaoming | 小萌| +----------+----------------------+ 1 row in set (0.06 sec)当然属性也可以作为查询条件mysql> select name, info->>'$.nick_name' from test_user where info->'$.nick_name'='小萌'; +----------+----------------------+ | name| info->>'$.nick_name' | +----------+----------------------+ | xiaoming | 小萌| +----------+----------------------+ 1 row in set (0.05 sec)值得一提的是,可以通过虚拟列对JSON类型的指定属性进行快速查询。

创建虚拟列:mysql> ALTER TABLE `test_user` ADD `nick_name` VARCHAR(50) GENERATED ALWAYS AS (info->>'$.nick_name') VIRTUAL;注意用操作符->>

使用时和普通类型的列查询是一样:mysql> select name,nick_name from test_user where nick_name='小萌'; +----------+-----------+ | name| nick_name | +----------+-----------+ | xiaoming | 小萌| +----------+-----------+ 1 row in set (0.05 sec)更新使用JSON_INSERT()插入新值,但不会覆盖已经存在的值mysql> UPDATE test_user SET info = JSON_INSERT(info, '$.sex', 1, '$.nick_name', '小花') where id=2;看下结果mysql> select * from test_user where id=2; +----+---------+--------------------------------------------+-----------+ | id | name| info| nick_name | +----+---------+--------------------------------------------+-----------+ |2 | xiaohua | {"age": 17, "sex": 0, "nick_name": "小花"} | 小花| +----+---------+--------------------------------------------+-----------+ 1 row in set (0.06 sec)使用JSON_SET()插入新值,并覆盖已经存在的值mysql> UPDATE test_user SET info = JSON_INSERT(info, '$.sex', 0, '$.nick_name', '小张') where id=3;看下结果mysql> select * from test_user where id=3; +----+-----------+---------------------------------------------------------------+-----------+ | id | name| info| nick_name | +----+-----------+---------------------------------------------------------------+-----------+ |3 | xiaozhang | {"age": 19, "sex": 1, "tag": [3, 5, 90], "nick_name": "小张"} | 小张| +----+-----------+---------------------------------------------------------------+-----------+ 1 row in set (0.06 sec)使用JSON_REPLACE()只替换存在的值mysql> UPDATE test_user SET info = JSON_REPLACE(info, '$.sex', 1, '$.tag', '[1,2,3]') where id=2;看下结果mysql> select * from test_user where id=2; +----+---------+--------------------------------------------+-----------+ | id | name| info| nick_name | +----+---------+--------------------------------------------+-----------+ |2 | xiaohua | {"age": 17, "sex": 1, "nick_name": "小花"} | 小花| +----+---------+--------------------------------------------+-----------+ 1 row in set (0.06 sec)可以看到tag没有更新进去

删除

使用JSON_REMOVE()删除JSON元素mysql> UPDATE test_user SET info = JSON_REMOVE(info, '$.sex', '$.tag') where id=1;看下结果mysql> select * from test_user where id=1; +----+----------+----------------------------------+-----------+ | id | name| info| nick_name | +----+----------+----------------------------------+-----------+ |1 | xiaoming | {"age": 18, "nick_name": "小萌"} | 小萌| +----+----------+----------------------------------+-----------+ 1 row in set (0.05 sec)本篇文章到这里就已经全部结束了,更多其他精彩内容可以关注PHP中文网的MySQL教程视频栏目!以上就是MySQL5.7的JSON基本操作(代码示例)的详细内容,更多请关注小潘博客其它相关文章!